MATLAB:Ordinary Differential Equations/Examples

The following examples show different ways of setting up and solving initial value problems in MATLAB. It is part of the page on Ordinary Differential Equations in MATLAB.

Examples

Note - each example began with the Templates provided at this web site. Some comments have been removed from the templates to conserve space while some comments may have been added to provide a clearer explanation of the process for a particular example.

Constant Rate of Change

Result using constant rate of change.

If the dependent variable has a constant rate of change:

\( \begin{align} \frac{dy}{dt}=k \end{align} \)

where \(k\) is some constant, you can provide the differential equation with a function called ConstDiff.m that contains the code:

function dydt = ConstDiff(t, y, k)
% Differential equation for constant growth
% t is time
% y is the state vector
% k contains any required constants
% dydt must be a column vector
dydt = k(1); % or just k since there is only one

You could calculate answers using this model with the following code called RunConstDiff.m, which assumes there are 100 evenly spaced times between 0 and 10, the initial value of \(y\) is 6, and the rate of change is 1.2:

% Initialize workspace and graph
clear; format short e; figure(1); clf

% Set name of file containing derivatives
DiffFileName = 'ConstDiff';

% Set up time span, initial value(s), and constant(s)
% Note: Variables should be in columns
tspan = linspace(0, 10);
yinit = 6;
k = 1.2;

% Determine if states should be plotted
PlotStates = 1;

%% Under the hood
% Use ODE function of choice to get output times and states
DE = eval(sprintf('@(t, y, k) %s(t,y,k)', DiffFileName))
[tout, yout] = ode45(@(t,y) DE(t,y,k), tspan, yinit);

% Plot results
if PlotStates
    figure(1); clf
    StatePlotter(tout, yout)
end

Time-dependent Rate of Change

Result using time-varying rate of change

If the dependent variable's rate of change is some function of time, this can be easily written using MATLAB. For example, if the differential equation is some quadratic function given as:

\( \begin{align} \frac{dy}{dt}&=k_1t^2+k_2t+k_3 \end{align} \)

then the function providing the values of the derivative may be written in a file called TimeDiff.m

function dydt = TimeDiff(t, y, k)
% Differential equation for time-based polynomial derivative
% t is time
% y is the state vector
% k contains any required constants
% dydt must be a column vector
dydt = polyval(k, t);

You could calculate answers using this model with the following code called RunTimeDiff.m, which assumes there are 20 evenly spaced times between 0 and 4, the initial value of \(y\) is 6, and the polynomial is defined by the vector [2 -6 3]:

% Initialize workspace and graph
clear; format short e; figure(1); clf

% Set name of file containing derivatives
DiffFileName = 'TimeDiff';

% Set up time span, initial value(s), and constant(s)
% Note: Variables should be in columns
tspan = linspace(0, 4, 20);
yinit = 6;
k     = [2 -6 3];

% Determine if states should be plotted
PlotStates = 1;

%% Under the hood
% Use ODE function of choice to get output times and states
DE = eval(sprintf('@(t, y, k) %s(t,y,k)', DiffFileName))
[tout, yout] = ode45(@(t,y) DE(t,y,k), tspan, yinit);

% Plot results
if PlotStates
    StatePlotter(tout, yout)
end

Population Growth

Result using rate of change proportional to measurement

For population growth, the rate of change of population is dependent upon the number of people as well as some constant of proportionality:

\( \begin{align} \frac{dy}{dt}=k\cdot y \end{align} \)

where \(k\) is again some constant. In that case, the function may be written in a file called PopDiff.m as follows:

function dydt = PopDiff(t, y, k)
% Differential equation for population growth
% t is time
% y is the state vector
% k contains any required constants
% dydt must be a column vector
dydt = k(1)*y(1); % or just k*y since both are 1x1

The following code, RunPopDiff.m, will calculate the population for a span of 3 seconds with 25 points for the population model above with an initial population of 10 and a constant of proportionality of 1.02:

% Initialize workspace and graph
clear; format short e; figure(1); clf

% Set name of file containing derivatives
DiffFileName = 'PopDiff';

% Set up time span, initial value(s), and constant(s)
% Note: Variables should be in columns
tspan = linspace(0, 3, 25);
yinit = 10;
k     = 1.02;

% Determine if states should be plotted
PlotStates = 1;

%% Under the hood
% Use ODE function of choice to get output times and states
DE = eval(sprintf('@(t, y, k) %s(t,y,k)', DiffFileName))
[tout, yout] = ode45(@(t,y) DE(t,y,k), tspan, yinit);

% Plot results
if PlotStates
    StatePlotter(tout, yout)
end

Multiple Variable Models

Result for system with two variables

It is possible to solve multiple-variable systems by making sure the differential function returns values for each of the variables. For instance, in the following system the first variable's rate of change depends only on time while the second is dependent upon both time and the first variable:

\( \begin{align} \frac{dy_1}{dt}&=k_1\cos(k_2t) & \frac{dy_2}{dt}&=k_3y_1+k_4t \end{align} \)

The differential file TwoDiff.m for this system will have a 2x1 matrix as the output:

function dydt = TwoDiff(t, y, k)
% Differential equations for two variables
% t is time
% y is the state vector
% k contains any required constants
% dydt must be a column vector
dydt = [...
    k(1)*cos(k(2)*t);...
    k(3)*y(1)+k(4)*t];

Finally, if you have systems with multiple dependent variables, just be sure to put the initial conditions in a column vector. For example, with the system defined as:

\( \begin{align} \frac{dy_1}{dt}&=4\cos(3t) & \frac{dy_2}{dt}&=-2y_1+0.5t \end{align} \)

you could use the following script called RunTwoDiff to solve for both \(y_1\) and \(y_2\) assuming \(y_1\) starts as 0 and \(y_2\) starts at -3:

% Initialize workspace and graph
clear; format short e; figure(1); clf

% Set name of file containing derivatives
DiffFileName = 'TwoDiff';

% Set up time span, initial value(s), and constant(s)
% Note: Variables should be in columns
tspan = linspace(0, 5);
yinit = [0 -3]';
k     = [4 3 -2 0.5];

% Determine if states should be plotted
PlotStates = 1;

%% Under the hood
% Use ODE function of choice to get output times and states
DE = eval(sprintf('@(t, y, k) %s(t,y,k)', DiffFileName))
[tout, yout] = ode45(@(t,y) DE(t,y,k), tspan, yinit);

% Plot results
if PlotStates
    StatePlotter(tout, yout)
end

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